``++object.Equals()++`` overrides can be optimized by checking first for reference equality between ``++this++`` and the parameter. This check can be implemented by calling ``++object.ReferenceEquals()++`` or ``++base.Equals()++``, where ``++base++`` is ``++object++``. However, using ``++base.Equals()++`` is a maintenance hazard because while it works if you extend ``++Object++`` directly, if you introduce a new base class that overrides ``++Equals++``, it suddenly stops working.


This rule raises an issue if ``++base.Equals()++`` is used but ``++base++`` is not ``++object++``.


== Noncompliant Code Example

----
class Base
{
  private int baseField;

  public override bool Equals(object other)
  {
    if (base.Equals(other)) // Okay; base is object
    {
      return true;
    }

    return this.baseField == ((Base)other).baseField;
  }
}

class Derived : Base
{
  private int derivedField;

  public override bool Equals(object other)
  {
    if (base.Equals(other))  // Noncompliant
    {
      return true;
    }

    return this.derivedField == ((Derived)other).derivedField;
  }
}
----


== Compliant Solution

----
class Base
{
  private int baseField;

  public override bool Equals(object other)
  {
    if (object.ReferenceEquals(this, other))  // base.Equals is okay here, but object.ReferenceEquals is better
    {
      return true;
    }

    return this.baseField == ((Base)other).baseField;
  }
}

class Derived : Base
{
  private int derivedField;

  public override bool Equals(object other)
  {
    if (object.ReferenceEquals(this, other))
    {
      return true;
    }

    return base.Equals(other) && this.derivedField == ((Derived)other).derivedField;
  }
}
----

