rspec/rules/S4351/java/rule.adoc

When implementing the ``++Comparable<T>.compareTo++`` method, the parameter's type has to match the type used in the ``++Comparable++`` declaration. When a different type is used this creates an overload instead of an override, which is unlikely to be the intent.


This rule raises an issue when the parameter of the ``++compareTo++`` method of a class implementing ``++Comparable<T>++`` is not same as the one used in the ``++Comparable++`` declaration.


== Noncompliant Code Example

----
public class Foo {
  static class Bar implements Comparable<Bar> {
    public int compareTo(Bar rhs) {
      return -1;
    }
  }

  static class FooBar extends Bar {
    public int compareTo(FooBar rhs) {  // Noncompliant: Parameter should be of type Bar
      return 0;
    }
  }
}
----


== Compliant Solution

----
public class Foo {
  static class Bar implements Comparable<Bar> {
    public int compareTo(Bar rhs) {
      return -1;
    }
  }

  static class FooBar extends Bar {
    public int compareTo(Bar rhs) {
      return 0;
    }
  }
}
----

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== Implementation Specification
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