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== Why is this an issue?
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The TypeScript compiler automatically casts a variable to the relevant type inside conditionals where it is possible to infer the type (because ``++typeof++``, ``++instanceof++``, etc was used). This compiler feature makes casts and not-``++null++`` assertions unnecessary.
=== Noncompliant code example
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[source,javascript]
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----
function getName(x?: string | UserName) {
if (x) {
console.log("Getting name for " + x!); // Noncompliant
if (typeof x === "string")
return (x as string); // Noncompliant
else
return (x as UserName).name; // Noncompliant
}
return "NoName";
}
----
=== Compliant solution
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[source,javascript]
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----
function getName(x?: string | UserName) {
if (x) {
console.log("Getting name for " + x);
if (typeof x === "string")
return x;
else
return x.name;
}
return "NoName";
}
----
ifdef::env-github,rspecator-view[]
'''
== Implementation Specification
(visible only on this page)
=== Message
Remove this unnecessary [cast|not-null assertion].
=== Highlighting
The cast or not-null assertion.
'''
== Comments And Links
(visible only on this page)
=== on 14 Nov 2017, 20:56:16 Ann Campbell wrote:
\[~jeanchristophe.collet] "and when property values set at type definition are checked" is not clear to me. Would it be fair to reword to something like:
____
inside conditions that test the object type, either with ``++.kind++`` or ``++instanceof++``
____
?
endif::env-github,rspecator-view[]