When implementing the ``++Comparable<T>.compareTo++`` method, the parameter's type has to match the type used in the ``++Comparable++`` declaration. When a different type is used this creates an overload instead of an override, which is unlikely to be the intent.
This rule raises an issue when the parameter of the ``++compareTo++`` method of a class implementing ``++Comparable<T>++`` is not same as the one used in the ``++Comparable++`` declaration.