The dangling ``++else++`` problem appears when nested ``++if++``/``++else++`` statements are written without curly braces. In this case, ``++else++`` is associated with the nearest ``++if++`` but that is not always obvious and sometimes the indentation can also be misleading.


This rules reports ``++else++`` statements that are difficult to understand, because they are inside nested ``++if++`` statements without curly braces.


Adding curly braces can generally make the code clearer (see rule S121 ), and in this situation of dangling ``++else++``, it really clarifies the intention of the code.


== Noncompliant Code Example

----
 if (a) 
   if (b) 
     d++; 
 else     // Noncompliant, is the "else" associated with "if(a)" or "if (b)"? (the answer is "if(b)")
   e++;
----


== Compliant Solution

----
 if (a) {
   if (b) {
     d++;
   } 
 } else { // Compliant, there is no doubt the "else" is associated with "if(a)"
   e++;
 }
----


== See

* https://en.wikipedia.org/wiki/Dangling_else