rspec/rules/S3253/csharp/rule.adoc
2021-04-28 18:08:03 +02:00

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Since the compiler will automatically invoke the base type's no-argument constructor, there's no need to specify its invocation explicitly. Also, when only a single ``++public++`` parameterless constructor is defined in a class, then that constructor can be removed because the compiler would generate it automatically. Similarly, empty ``++static++`` constructors and empty destructors are also wasted keystrokes.
== Noncompliant Code Example
----
class X
{
public X() { } // Noncompliant
static X() { } // Noncompliant
~X() { } // Noncompliant
...
}
class Y : X
{
public Y(int parameter) : base() // Noncompliant
{
/* does something with the parameter */
}
}
----
== Compliant Solution
----
class X
{
...
}
class Y : X
{
public Y(int parameter)
{
/* does something with the parameter */
}
}
----