54 lines
1.5 KiB
Plaintext
54 lines
1.5 KiB
Plaintext
A bare ``++raise++`` statement, i.e. a ``++raise++`` with no exception provided, will re-raise the last active exception in the current scope. If no exception is active a ``++RuntimeError++`` is raised instead.
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If the bare "raise" statement is in a ``++finally++`` block, it will only have an active exception to re-raise when an exception from the ``++try++`` block is not caught or when an exception is raised by an ``++except++`` or ``++else++`` block. Thus bare ``++raise++`` statements should not be relied upon in ``++finally++`` blocks. It is simpler to let the exception raise automatically.
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This rule raises an issue when a bare ``++raise++`` statements is in a ``++finally++`` block.
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== Noncompliant Code Example
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----
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def foo(param):
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result = 0
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try:
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print("foo")
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except ValueError as e:
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pass
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else:
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if param:
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raise ValueError()
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finally:
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if param:
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raise # Noncompliant. This will fail in some context.
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else:
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result = 1
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return result
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----
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== Compliant Solution
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----
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def foo(param):
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result = 0
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try:
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print("foo")
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except ValueError as e:
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pass
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else:
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if param:
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raise ValueError()
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finally:
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if not param:
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result = 1
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# the exception will raise automatically
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return result
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----
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== See
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* Python Documentation - https://docs.python.org/3/reference/simple_stmts.html#raise[The ``++raise++`` statement]
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